| /* |
| * Copyright 2014 The Android Open Source Project |
| * |
| * Licensed under the Apache License, Version 2.0 (the "License"); |
| * you may not use this file except in compliance with the License. |
| * You may obtain a copy of the License at |
| * |
| * http://www.apache.org/licenses/LICENSE-2.0 |
| * |
| * Unless required by applicable law or agreed to in writing, software |
| * distributed under the License is distributed on an "AS IS" BASIS, |
| * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. |
| * See the License for the specific language governing permissions and |
| * limitations under the License. |
| */ |
| |
| package android.support.v7.graphics; |
| |
| import java.util.Arrays; |
| |
| /** |
| * Class which provides a histogram for RGB values. |
| */ |
| final class ColorHistogram { |
| |
| private final int[] mColors; |
| private final int[] mColorCounts; |
| private final int mNumberColors; |
| |
| /** |
| * A new {@link ColorHistogram} instance. |
| * |
| * @param pixels array of image contents |
| */ |
| ColorHistogram(final int[] pixels) { |
| // Sort the pixels to enable counting below |
| Arrays.sort(pixels); |
| |
| // Count number of distinct colors |
| mNumberColors = countDistinctColors(pixels); |
| |
| // Create arrays |
| mColors = new int[mNumberColors]; |
| mColorCounts = new int[mNumberColors]; |
| |
| // Finally count the frequency of each color |
| countFrequencies(pixels); |
| } |
| |
| /** |
| * @return number of distinct colors in the image. |
| */ |
| int getNumberOfColors() { |
| return mNumberColors; |
| } |
| |
| /** |
| * @return an array containing all of the distinct colors in the image. |
| */ |
| int[] getColors() { |
| return mColors; |
| } |
| |
| /** |
| * @return an array containing the frequency of a distinct colors within the image. |
| */ |
| int[] getColorCounts() { |
| return mColorCounts; |
| } |
| |
| private static int countDistinctColors(final int[] pixels) { |
| if (pixels.length < 2) { |
| // If we have less than 2 pixels we can stop here |
| return pixels.length; |
| } |
| |
| // If we have at least 2 pixels, we have a minimum of 1 color... |
| int colorCount = 1; |
| int currentColor = pixels[0]; |
| |
| // Now iterate from the second pixel to the end, counting distinct colors |
| for (int i = 1; i < pixels.length; i++) { |
| // If we encounter a new color, increase the population |
| if (pixels[i] != currentColor) { |
| currentColor = pixels[i]; |
| colorCount++; |
| } |
| } |
| |
| return colorCount; |
| } |
| |
| private void countFrequencies(final int[] pixels) { |
| if (pixels.length == 0) { |
| return; |
| } |
| |
| int currentColorIndex = 0; |
| int currentColor = pixels[0]; |
| |
| mColors[currentColorIndex] = currentColor; |
| mColorCounts[currentColorIndex] = 1; |
| |
| if (pixels.length == 1) { |
| // If we only have one pixel, we can stop here |
| return; |
| } |
| |
| // Now iterate from the second pixel to the end, population distinct colors |
| for (int i = 1; i < pixels.length; i++) { |
| if (pixels[i] == currentColor) { |
| // We've hit the same color as before, increase population |
| mColorCounts[currentColorIndex]++; |
| } else { |
| // We've hit a new color, increase index |
| currentColor = pixels[i]; |
| |
| currentColorIndex++; |
| mColors[currentColorIndex] = currentColor; |
| mColorCounts[currentColorIndex] = 1; |
| } |
| } |
| } |
| |
| } |