| ## Module statistics.py | |
| ## | |
| ## Copyright (c) 2013 Steven D'Aprano <steve+python@pearwood.info>. | |
| ## | |
| ## Licensed under the Apache License, Version 2.0 (the "License"); | |
| ## you may not use this file except in compliance with the License. | |
| ## You may obtain a copy of the License at | |
| ## | |
| ## http://www.apache.org/licenses/LICENSE-2.0 | |
| ## | |
| ## Unless required by applicable law or agreed to in writing, software | |
| ## distributed under the License is distributed on an "AS IS" BASIS, | |
| ## WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | |
| ## See the License for the specific language governing permissions and | |
| ## limitations under the License. | |
| """ | |
| Basic statistics module. | |
| This module provides functions for calculating statistics of data, including | |
| averages, variance, and standard deviation. | |
| Calculating averages | |
| -------------------- | |
| ================== ============================================= | |
| Function Description | |
| ================== ============================================= | |
| mean Arithmetic mean (average) of data. | |
| median Median (middle value) of data. | |
| median_low Low median of data. | |
| median_high High median of data. | |
| median_grouped Median, or 50th percentile, of grouped data. | |
| mode Mode (most common value) of data. | |
| ================== ============================================= | |
| Calculate the arithmetic mean ("the average") of data: | |
| >>> mean([-1.0, 2.5, 3.25, 5.75]) | |
| 2.625 | |
| Calculate the standard median of discrete data: | |
| >>> median([2, 3, 4, 5]) | |
| 3.5 | |
| Calculate the median, or 50th percentile, of data grouped into class intervals | |
| centred on the data values provided. E.g. if your data points are rounded to | |
| the nearest whole number: | |
| >>> median_grouped([2, 2, 3, 3, 3, 4]) #doctest: +ELLIPSIS | |
| 2.8333333333... | |
| This should be interpreted in this way: you have two data points in the class | |
| interval 1.5-2.5, three data points in the class interval 2.5-3.5, and one in | |
| the class interval 3.5-4.5. The median of these data points is 2.8333... | |
| Calculating variability or spread | |
| --------------------------------- | |
| ================== ============================================= | |
| Function Description | |
| ================== ============================================= | |
| pvariance Population variance of data. | |
| variance Sample variance of data. | |
| pstdev Population standard deviation of data. | |
| stdev Sample standard deviation of data. | |
| ================== ============================================= | |
| Calculate the standard deviation of sample data: | |
| >>> stdev([2.5, 3.25, 5.5, 11.25, 11.75]) #doctest: +ELLIPSIS | |
| 4.38961843444... | |
| If you have previously calculated the mean, you can pass it as the optional | |
| second argument to the four "spread" functions to avoid recalculating it: | |
| >>> data = [1, 2, 2, 4, 4, 4, 5, 6] | |
| >>> mu = mean(data) | |
| >>> pvariance(data, mu) | |
| 2.5 | |
| Exceptions | |
| ---------- | |
| A single exception is defined: StatisticsError is a subclass of ValueError. | |
| """ | |
| __all__ = [ 'StatisticsError', | |
| 'pstdev', 'pvariance', 'stdev', 'variance', | |
| 'median', 'median_low', 'median_high', 'median_grouped', | |
| 'mean', 'mode', | |
| ] | |
| import collections | |
| import math | |
| from fractions import Fraction | |
| from decimal import Decimal | |
| from itertools import groupby | |
| # === Exceptions === | |
| class StatisticsError(ValueError): | |
| pass | |
| # === Private utilities === | |
| def _sum(data, start=0): | |
| """_sum(data [, start]) -> (type, sum, count) | |
| Return a high-precision sum of the given numeric data as a fraction, | |
| together with the type to be converted to and the count of items. | |
| If optional argument ``start`` is given, it is added to the total. | |
| If ``data`` is empty, ``start`` (defaulting to 0) is returned. | |
| Examples | |
| -------- | |
| >>> _sum([3, 2.25, 4.5, -0.5, 1.0], 0.75) | |
| (<class 'float'>, Fraction(11, 1), 5) | |
| Some sources of round-off error will be avoided: | |
| >>> _sum([1e50, 1, -1e50] * 1000) # Built-in sum returns zero. | |
| (<class 'float'>, Fraction(1000, 1), 3000) | |
| Fractions and Decimals are also supported: | |
| >>> from fractions import Fraction as F | |
| >>> _sum([F(2, 3), F(7, 5), F(1, 4), F(5, 6)]) | |
| (<class 'fractions.Fraction'>, Fraction(63, 20), 4) | |
| >>> from decimal import Decimal as D | |
| >>> data = [D("0.1375"), D("0.2108"), D("0.3061"), D("0.0419")] | |
| >>> _sum(data) | |
| (<class 'decimal.Decimal'>, Fraction(6963, 10000), 4) | |
| Mixed types are currently treated as an error, except that int is | |
| allowed. | |
| """ | |
| count = 0 | |
| n, d = _exact_ratio(start) | |
| partials = {d: n} | |
| partials_get = partials.get | |
| T = _coerce(int, type(start)) | |
| for typ, values in groupby(data, type): | |
| T = _coerce(T, typ) # or raise TypeError | |
| for n,d in map(_exact_ratio, values): | |
| count += 1 | |
| partials[d] = partials_get(d, 0) + n | |
| if None in partials: | |
| # The sum will be a NAN or INF. We can ignore all the finite | |
| # partials, and just look at this special one. | |
| total = partials[None] | |
| assert not _isfinite(total) | |
| else: | |
| # Sum all the partial sums using builtin sum. | |
| # FIXME is this faster if we sum them in order of the denominator? | |
| total = sum(Fraction(n, d) for d, n in sorted(partials.items())) | |
| return (T, total, count) | |
| def _isfinite(x): | |
| try: | |
| return x.is_finite() # Likely a Decimal. | |
| except AttributeError: | |
| return math.isfinite(x) # Coerces to float first. | |
| def _coerce(T, S): | |
| """Coerce types T and S to a common type, or raise TypeError. | |
| Coercion rules are currently an implementation detail. See the CoerceTest | |
| test class in test_statistics for details. | |
| """ | |
| # See http://bugs.python.org/issue24068. | |
| assert T is not bool, "initial type T is bool" | |
| # If the types are the same, no need to coerce anything. Put this | |
| # first, so that the usual case (no coercion needed) happens as soon | |
| # as possible. | |
| if T is S: return T | |
| # Mixed int & other coerce to the other type. | |
| if S is int or S is bool: return T | |
| if T is int: return S | |
| # If one is a (strict) subclass of the other, coerce to the subclass. | |
| if issubclass(S, T): return S | |
| if issubclass(T, S): return T | |
| # Ints coerce to the other type. | |
| if issubclass(T, int): return S | |
| if issubclass(S, int): return T | |
| # Mixed fraction & float coerces to float (or float subclass). | |
| if issubclass(T, Fraction) and issubclass(S, float): | |
| return S | |
| if issubclass(T, float) and issubclass(S, Fraction): | |
| return T | |
| # Any other combination is disallowed. | |
| msg = "don't know how to coerce %s and %s" | |
| raise TypeError(msg % (T.__name__, S.__name__)) | |
| def _exact_ratio(x): | |
| """Return Real number x to exact (numerator, denominator) pair. | |
| >>> _exact_ratio(0.25) | |
| (1, 4) | |
| x is expected to be an int, Fraction, Decimal or float. | |
| """ | |
| try: | |
| # Optimise the common case of floats. We expect that the most often | |
| # used numeric type will be builtin floats, so try to make this as | |
| # fast as possible. | |
| if type(x) is float: | |
| return x.as_integer_ratio() | |
| try: | |
| # x may be an int, Fraction, or Integral ABC. | |
| return (x.numerator, x.denominator) | |
| except AttributeError: | |
| try: | |
| # x may be a float subclass. | |
| return x.as_integer_ratio() | |
| except AttributeError: | |
| try: | |
| # x may be a Decimal. | |
| return _decimal_to_ratio(x) | |
| except AttributeError: | |
| # Just give up? | |
| pass | |
| except (OverflowError, ValueError): | |
| # float NAN or INF. | |
| assert not math.isfinite(x) | |
| return (x, None) | |
| msg = "can't convert type '{}' to numerator/denominator" | |
| raise TypeError(msg.format(type(x).__name__)) | |
| # FIXME This is faster than Fraction.from_decimal, but still too slow. | |
| def _decimal_to_ratio(d): | |
| """Convert Decimal d to exact integer ratio (numerator, denominator). | |
| >>> from decimal import Decimal | |
| >>> _decimal_to_ratio(Decimal("2.6")) | |
| (26, 10) | |
| """ | |
| sign, digits, exp = d.as_tuple() | |
| if exp in ('F', 'n', 'N'): # INF, NAN, sNAN | |
| assert not d.is_finite() | |
| return (d, None) | |
| num = 0 | |
| for digit in digits: | |
| num = num*10 + digit | |
| if exp < 0: | |
| den = 10**-exp | |
| else: | |
| num *= 10**exp | |
| den = 1 | |
| if sign: | |
| num = -num | |
| return (num, den) | |
| def _convert(value, T): | |
| """Convert value to given numeric type T.""" | |
| if type(value) is T: | |
| # This covers the cases where T is Fraction, or where value is | |
| # a NAN or INF (Decimal or float). | |
| return value | |
| if issubclass(T, int) and value.denominator != 1: | |
| T = float | |
| try: | |
| # FIXME: what do we do if this overflows? | |
| return T(value) | |
| except TypeError: | |
| if issubclass(T, Decimal): | |
| return T(value.numerator)/T(value.denominator) | |
| else: | |
| raise | |
| def _counts(data): | |
| # Generate a table of sorted (value, frequency) pairs. | |
| table = collections.Counter(iter(data)).most_common() | |
| if not table: | |
| return table | |
| # Extract the values with the highest frequency. | |
| maxfreq = table[0][1] | |
| for i in range(1, len(table)): | |
| if table[i][1] != maxfreq: | |
| table = table[:i] | |
| break | |
| return table | |
| # === Measures of central tendency (averages) === | |
| def mean(data): | |
| """Return the sample arithmetic mean of data. | |
| >>> mean([1, 2, 3, 4, 4]) | |
| 2.8 | |
| >>> from fractions import Fraction as F | |
| >>> mean([F(3, 7), F(1, 21), F(5, 3), F(1, 3)]) | |
| Fraction(13, 21) | |
| >>> from decimal import Decimal as D | |
| >>> mean([D("0.5"), D("0.75"), D("0.625"), D("0.375")]) | |
| Decimal('0.5625') | |
| If ``data`` is empty, StatisticsError will be raised. | |
| """ | |
| if iter(data) is data: | |
| data = list(data) | |
| n = len(data) | |
| if n < 1: | |
| raise StatisticsError('mean requires at least one data point') | |
| T, total, count = _sum(data) | |
| assert count == n | |
| return _convert(total/n, T) | |
| # FIXME: investigate ways to calculate medians without sorting? Quickselect? | |
| def median(data): | |
| """Return the median (middle value) of numeric data. | |
| When the number of data points is odd, return the middle data point. | |
| When the number of data points is even, the median is interpolated by | |
| taking the average of the two middle values: | |
| >>> median([1, 3, 5]) | |
| 3 | |
| >>> median([1, 3, 5, 7]) | |
| 4.0 | |
| """ | |
| data = sorted(data) | |
| n = len(data) | |
| if n == 0: | |
| raise StatisticsError("no median for empty data") | |
| if n%2 == 1: | |
| return data[n//2] | |
| else: | |
| i = n//2 | |
| return (data[i - 1] + data[i])/2 | |
| def median_low(data): | |
| """Return the low median of numeric data. | |
| When the number of data points is odd, the middle value is returned. | |
| When it is even, the smaller of the two middle values is returned. | |
| >>> median_low([1, 3, 5]) | |
| 3 | |
| >>> median_low([1, 3, 5, 7]) | |
| 3 | |
| """ | |
| data = sorted(data) | |
| n = len(data) | |
| if n == 0: | |
| raise StatisticsError("no median for empty data") | |
| if n%2 == 1: | |
| return data[n//2] | |
| else: | |
| return data[n//2 - 1] | |
| def median_high(data): | |
| """Return the high median of data. | |
| When the number of data points is odd, the middle value is returned. | |
| When it is even, the larger of the two middle values is returned. | |
| >>> median_high([1, 3, 5]) | |
| 3 | |
| >>> median_high([1, 3, 5, 7]) | |
| 5 | |
| """ | |
| data = sorted(data) | |
| n = len(data) | |
| if n == 0: | |
| raise StatisticsError("no median for empty data") | |
| return data[n//2] | |
| def median_grouped(data, interval=1): | |
| """Return the 50th percentile (median) of grouped continuous data. | |
| >>> median_grouped([1, 2, 2, 3, 4, 4, 4, 4, 4, 5]) | |
| 3.7 | |
| >>> median_grouped([52, 52, 53, 54]) | |
| 52.5 | |
| This calculates the median as the 50th percentile, and should be | |
| used when your data is continuous and grouped. In the above example, | |
| the values 1, 2, 3, etc. actually represent the midpoint of classes | |
| 0.5-1.5, 1.5-2.5, 2.5-3.5, etc. The middle value falls somewhere in | |
| class 3.5-4.5, and interpolation is used to estimate it. | |
| Optional argument ``interval`` represents the class interval, and | |
| defaults to 1. Changing the class interval naturally will change the | |
| interpolated 50th percentile value: | |
| >>> median_grouped([1, 3, 3, 5, 7], interval=1) | |
| 3.25 | |
| >>> median_grouped([1, 3, 3, 5, 7], interval=2) | |
| 3.5 | |
| This function does not check whether the data points are at least | |
| ``interval`` apart. | |
| """ | |
| data = sorted(data) | |
| n = len(data) | |
| if n == 0: | |
| raise StatisticsError("no median for empty data") | |
| elif n == 1: | |
| return data[0] | |
| # Find the value at the midpoint. Remember this corresponds to the | |
| # centre of the class interval. | |
| x = data[n//2] | |
| for obj in (x, interval): | |
| if isinstance(obj, (str, bytes)): | |
| raise TypeError('expected number but got %r' % obj) | |
| try: | |
| L = x - interval/2 # The lower limit of the median interval. | |
| except TypeError: | |
| # Mixed type. For now we just coerce to float. | |
| L = float(x) - float(interval)/2 | |
| cf = data.index(x) # Number of values below the median interval. | |
| # FIXME The following line could be more efficient for big lists. | |
| f = data.count(x) # Number of data points in the median interval. | |
| return L + interval*(n/2 - cf)/f | |
| def mode(data): | |
| """Return the most common data point from discrete or nominal data. | |
| ``mode`` assumes discrete data, and returns a single value. This is the | |
| standard treatment of the mode as commonly taught in schools: | |
| >>> mode([1, 1, 2, 3, 3, 3, 3, 4]) | |
| 3 | |
| This also works with nominal (non-numeric) data: | |
| >>> mode(["red", "blue", "blue", "red", "green", "red", "red"]) | |
| 'red' | |
| If there is not exactly one most common value, ``mode`` will raise | |
| StatisticsError. | |
| """ | |
| # Generate a table of sorted (value, frequency) pairs. | |
| table = _counts(data) | |
| if len(table) == 1: | |
| return table[0][0] | |
| elif table: | |
| raise StatisticsError( | |
| 'no unique mode; found %d equally common values' % len(table) | |
| ) | |
| else: | |
| raise StatisticsError('no mode for empty data') | |
| # === Measures of spread === | |
| # See http://mathworld.wolfram.com/Variance.html | |
| # http://mathworld.wolfram.com/SampleVariance.html | |
| # http://en.wikipedia.org/wiki/Algorithms_for_calculating_variance | |
| # | |
| # Under no circumstances use the so-called "computational formula for | |
| # variance", as that is only suitable for hand calculations with a small | |
| # amount of low-precision data. It has terrible numeric properties. | |
| # | |
| # See a comparison of three computational methods here: | |
| # http://www.johndcook.com/blog/2008/09/26/comparing-three-methods-of-computing-standard-deviation/ | |
| def _ss(data, c=None): | |
| """Return sum of square deviations of sequence data. | |
| If ``c`` is None, the mean is calculated in one pass, and the deviations | |
| from the mean are calculated in a second pass. Otherwise, deviations are | |
| calculated from ``c`` as given. Use the second case with care, as it can | |
| lead to garbage results. | |
| """ | |
| if c is None: | |
| c = mean(data) | |
| T, total, count = _sum((x-c)**2 for x in data) | |
| # The following sum should mathematically equal zero, but due to rounding | |
| # error may not. | |
| U, total2, count2 = _sum((x-c) for x in data) | |
| assert T == U and count == count2 | |
| total -= total2**2/len(data) | |
| assert not total < 0, 'negative sum of square deviations: %f' % total | |
| return (T, total) | |
| def variance(data, xbar=None): | |
| """Return the sample variance of data. | |
| data should be an iterable of Real-valued numbers, with at least two | |
| values. The optional argument xbar, if given, should be the mean of | |
| the data. If it is missing or None, the mean is automatically calculated. | |
| Use this function when your data is a sample from a population. To | |
| calculate the variance from the entire population, see ``pvariance``. | |
| Examples: | |
| >>> data = [2.75, 1.75, 1.25, 0.25, 0.5, 1.25, 3.5] | |
| >>> variance(data) | |
| 1.3720238095238095 | |
| If you have already calculated the mean of your data, you can pass it as | |
| the optional second argument ``xbar`` to avoid recalculating it: | |
| >>> m = mean(data) | |
| >>> variance(data, m) | |
| 1.3720238095238095 | |
| This function does not check that ``xbar`` is actually the mean of | |
| ``data``. Giving arbitrary values for ``xbar`` may lead to invalid or | |
| impossible results. | |
| Decimals and Fractions are supported: | |
| >>> from decimal import Decimal as D | |
| >>> variance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")]) | |
| Decimal('31.01875') | |
| >>> from fractions import Fraction as F | |
| >>> variance([F(1, 6), F(1, 2), F(5, 3)]) | |
| Fraction(67, 108) | |
| """ | |
| if iter(data) is data: | |
| data = list(data) | |
| n = len(data) | |
| if n < 2: | |
| raise StatisticsError('variance requires at least two data points') | |
| T, ss = _ss(data, xbar) | |
| return _convert(ss/(n-1), T) | |
| def pvariance(data, mu=None): | |
| """Return the population variance of ``data``. | |
| data should be an iterable of Real-valued numbers, with at least one | |
| value. The optional argument mu, if given, should be the mean of | |
| the data. If it is missing or None, the mean is automatically calculated. | |
| Use this function to calculate the variance from the entire population. | |
| To estimate the variance from a sample, the ``variance`` function is | |
| usually a better choice. | |
| Examples: | |
| >>> data = [0.0, 0.25, 0.25, 1.25, 1.5, 1.75, 2.75, 3.25] | |
| >>> pvariance(data) | |
| 1.25 | |
| If you have already calculated the mean of the data, you can pass it as | |
| the optional second argument to avoid recalculating it: | |
| >>> mu = mean(data) | |
| >>> pvariance(data, mu) | |
| 1.25 | |
| This function does not check that ``mu`` is actually the mean of ``data``. | |
| Giving arbitrary values for ``mu`` may lead to invalid or impossible | |
| results. | |
| Decimals and Fractions are supported: | |
| >>> from decimal import Decimal as D | |
| >>> pvariance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")]) | |
| Decimal('24.815') | |
| >>> from fractions import Fraction as F | |
| >>> pvariance([F(1, 4), F(5, 4), F(1, 2)]) | |
| Fraction(13, 72) | |
| """ | |
| if iter(data) is data: | |
| data = list(data) | |
| n = len(data) | |
| if n < 1: | |
| raise StatisticsError('pvariance requires at least one data point') | |
| ss = _ss(data, mu) | |
| T, ss = _ss(data, mu) | |
| return _convert(ss/n, T) | |
| def stdev(data, xbar=None): | |
| """Return the square root of the sample variance. | |
| See ``variance`` for arguments and other details. | |
| >>> stdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75]) | |
| 1.0810874155219827 | |
| """ | |
| var = variance(data, xbar) | |
| try: | |
| return var.sqrt() | |
| except AttributeError: | |
| return math.sqrt(var) | |
| def pstdev(data, mu=None): | |
| """Return the square root of the population variance. | |
| See ``pvariance`` for arguments and other details. | |
| >>> pstdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75]) | |
| 0.986893273527251 | |
| """ | |
| var = pvariance(data, mu) | |
| try: | |
| return var.sqrt() | |
| except AttributeError: | |
| return math.sqrt(var) |