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/* -*-C-*-
********************************************************************************
*
* File: outlines.c (Formerly outlines.c)
* Description: Combinatorial Splitter
* Author: Mark Seaman, OCR Technology
* Created: Thu Jul 27 08:59:01 1989
* Modified: Wed Jul 10 14:56:49 1991 (Mark Seaman) marks@hpgrlt
* Language: C
* Package: N/A
* Status: Experimental (Do Not Distribute)
*
* (c) Copyright 1989, Hewlett-Packard Company.
** Licensed under the Apache License, Version 2.0 (the "License");
** you may not use this file except in compliance with the License.
** You may obtain a copy of the License at
** http://www.apache.org/licenses/LICENSE-2.0
** Unless required by applicable law or agreed to in writing, software
** distributed under the License is distributed on an "AS IS" BASIS,
** WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
** See the License for the specific language governing permissions and
** limitations under the License.
*
********************************************************************************
* Revision 1.2 89/09/15 09:24:41 09:24:41 marks (Mark Seaman)
* First released version of Combinatorial splitter code
**/
/*----------------------------------------------------------------------
I n c l u d e s
----------------------------------------------------------------------*/
#include "outlines.h"
#ifdef __UNIX__
#include <assert.h>
#endif
/*----------------------------------------------------------------------
F u n c t i o n s
----------------------------------------------------------------------*/
/**********************************************************************
* crosses_outline
*
* Check to see if this line crosses over this outline. If it does
* return TRUE.
**********************************************************************/
int crosses_outline(EDGEPT *p0, /* Start of line */
EDGEPT *p1, /* End of line */
EDGEPT *outline) { /* Outline to check */
EDGEPT *pt = outline;
do {
if (is_crossed (p0->pos, p1->pos, pt->pos, pt->next->pos))
return (TRUE);
pt = pt->next;
}
while (pt != outline);
return (FALSE);
}
/**********************************************************************
* is_crossed
*
* Return TRUE when the two line segments cross each other. Find out
* where the projected lines would cross and then check to see if the
* point of intersection lies on both of the line segments. If it does
* then these two segments cross.
**********************************************************************/
int is_crossed(TPOINT a0, TPOINT a1, TPOINT b0, TPOINT b1) {
int b0a1xb0b1, b0b1xb0a0;
int a1b1xa1a0, a1a0xa1b0;
TPOINT b0a1, b0a0, a1b1, b0b1, a1a0;
b0a1.x = a1.x - b0.x;
b0a0.x = a0.x - b0.x;
a1b1.x = b1.x - a1.x;
b0b1.x = b1.x - b0.x;
a1a0.x = a0.x - a1.x;
b0a1.y = a1.y - b0.y;
b0a0.y = a0.y - b0.y;
a1b1.y = b1.y - a1.y;
b0b1.y = b1.y - b0.y;
a1a0.y = a0.y - a1.y;
b0a1xb0b1 = CROSS (b0a1, b0b1);
b0b1xb0a0 = CROSS (b0b1, b0a0);
a1b1xa1a0 = CROSS (a1b1, a1a0);
/*a1a0xa1b0=CROSS(a1a0,a1b0); */
a1a0xa1b0 = -CROSS (a1a0, b0a1);
return ((b0a1xb0b1 > 0 && b0b1xb0a0 > 0)
|| (b0a1xb0b1 < 0 && b0b1xb0a0 < 0))
&& ((a1b1xa1a0 > 0 && a1a0xa1b0 > 0) || (a1b1xa1a0 < 0 && a1a0xa1b0 < 0));
}
/**********************************************************************
* is_same_edgept
*
* Return true if the points are identical.
**********************************************************************/
int is_same_edgept(EDGEPT *p1, EDGEPT *p2) {
return (p1 == p2);
}
/**********************************************************************
* near_point
*
* Find the point on a line segment that is closest to a point not on
* the line segment. Return that point.
**********************************************************************/
EDGEPT *near_point(EDGEPT *point, EDGEPT *line_pt_0, EDGEPT *line_pt_1) {
TPOINT p;
float slope;
float intercept;
float x0 = line_pt_0->pos.x;
float x1 = line_pt_1->pos.x;
float y0 = line_pt_0->pos.y;
float y1 = line_pt_1->pos.y;
if (x0 == x1) {
/* Handle vertical line */
p.x = (inT16) x0;
p.y = point->pos.y;
}
else {
/* Slope and intercept */
slope = (y0 - y1) / (x0 - x1);
intercept = y1 - x1 * slope;
/* Find perpendicular */
p.x = (inT16) ((point->pos.x + (point->pos.y - intercept) * slope) /
(slope * slope + 1));
p.y = (inT16) (slope * p.x + intercept);
}
if (is_on_line (p, line_pt_0->pos, line_pt_1->pos) &&
(!same_point (p, line_pt_0->pos)) && (!same_point (p, line_pt_1->pos)))
/* Intersection on line */
return (make_edgept (p.x, p.y, line_pt_1, line_pt_0));
else /* Intersection not on line */
return (closest (point, line_pt_0, line_pt_1));
}
/**********************************************************************
* reverse_outline
*
* Change the direction of the outline. If it was clockwise make it
* counter-clockwise and vice versa. Do this by swapping each of the
* next and prev fields of each edge point.
**********************************************************************/
void reverse_outline(EDGEPT *outline) {
EDGEPT *edgept = outline;
EDGEPT *temp;
do {
/* Swap next and prev */
temp = edgept->prev;
edgept->prev = edgept->next;
edgept->next = temp;
/* Set up vec field */
edgept->vec.x = edgept->next->pos.x - edgept->pos.x;
edgept->vec.y = edgept->next->pos.y - edgept->pos.y;
edgept = edgept->prev; /* Go to next point */
}
while (edgept != outline);
}