commit | c43a9a46307525b6429736192b53e9b5216a6003 | [log] [tgz] |
---|---|---|
author | Android Build Coastguard Worker <android-build-coastguard-worker@google.com> | Tue Oct 10 23:07:47 2023 +0000 |
committer | Android Build Coastguard Worker <android-build-coastguard-worker@google.com> | Tue Oct 10 23:07:47 2023 +0000 |
tree | 1658cb90958498bab43d7ddd0aa2ef61be41ff5d | |
parent | 113cea9dd56acbe2700f1215797955c08bd42126 [diff] | |
parent | 19c5e177c75bcc802f5ac1c6e5b2db1d64f2e280 [diff] |
Snap for 10929834 from 19c5e177c75bcc802f5ac1c6e5b2db1d64f2e280 to sdk-release Change-Id: Ib50c96d852293f357a2a642a904b14a72012c209
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?