Bug: 132083173

Clone this repo:
  1. 917fd11 DO NOT MERGE - qt-qpr1-dev-plus-aosp-without-vendor@5915889 into stage-aosp-master by Xin Li · 4 months ago master android-r-preview-1
  2. ecd2315 Upgrade python/ipaddress to v1.0.23 am: 6a1ca2ef83 by Haibo Huang · 4 months ago
  3. 6a1ca2e Upgrade python/ipaddress to v1.0.23 by Haibo Huang · 4 months ago
  4. d8aef06 release 1.0.23 by Philipp Hagemeister · 4 months ago upstream-master
  5. f069b15 README: Clarify that we are backporting 3.8+, not 3.3 by Philipp Hagemeister · 4 months ago

ipaddress

Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.

This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.

Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:

>>> from __future__ import unicode_literals
>>> ipaddress.ip_address('1.2.3.4')
IPv4Address(u'1.2.3.4')

or

>>> ipaddress.ip_address(u'1.2.3.4')
IPv4Address(u'1.2.3.4')

but not:

>>> ipaddress.ip_address(b'1.2.3.4')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "ipaddress.py", line 163, in ip_address
    ' a unicode object?' % address)
ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?