commit | 5a1e983aa7393f541d214f285737882a7f6846bb | [log] [tgz] |
---|---|---|
author | Haibo Huang <hhb@google.com> | Mon Oct 21 16:24:44 2019 -0700 |
committer | android-build-merger <android-build-merger@google.com> | Mon Oct 21 16:24:44 2019 -0700 |
tree | e9fb14bd73b8f85c9c77b77ad76e7870a356acf0 | |
parent | 0bc80b4d61f9becdd7b672cd57db47974b414cea [diff] | |
parent | de6dd07eb357f27dd91d19e388db2f0ecef4a5bf [diff] |
Upgrade python/ipaddress to v1.0.23 am: 6a1ca2ef83 am: ecd2315d45 am: ca97a0e49c am: de6dd07eb3 Change-Id: I98e6b26ce4e857d8899f9d7218d5c3aeb8fcd9eb
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?