commit | dffab708bc8746f923c2806422d9f3386bc5327a | [log] [tgz] |
---|---|---|
author | Krzysztof Kosiński <krzysio@google.com> | Tue Sep 20 01:39:55 2022 +0000 |
committer | Krzysztof Kosiński <krzysio@google.com> | Tue Sep 20 01:41:19 2022 +0000 |
tree | 1658cb90958498bab43d7ddd0aa2ef61be41ff5d | |
parent | 8640dcfecb8596d172114e2ecba01f4887346c13 [diff] |
Disable unused Python 2 variant. Bug: 245854393 Test: presubmit Change-Id: I00ce509a79197e65a51729682d4539a0215ac052
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?