commit | ca97a0e49cadd939e12c76cc684dae546cf4a4e7 | [log] [tgz] |
---|---|---|
author | Haibo Huang <hhb@google.com> | Mon Oct 21 16:08:39 2019 -0700 |
committer | android-build-merger <android-build-merger@google.com> | Mon Oct 21 16:08:39 2019 -0700 |
tree | e9fb14bd73b8f85c9c77b77ad76e7870a356acf0 | |
parent | 2458372292f3098ed1a8665077692de16a63ba5d [diff] | |
parent | ecd2315d45ff33094935cc7bda76f8d3b0f08914 [diff] |
Upgrade python/ipaddress to v1.0.23 am: 6a1ca2ef83 am: ecd2315d45 Change-Id: I684d0d3be4b8b0560e17d37072add58fa8c978b9
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?