commit | a3b1237ba86026ebf07c44ef95c6678028456b5a | [log] [tgz] |
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author | Philipp Hagemeister <phihag@phihag.de> | Fri Sep 09 19:02:04 2016 +0200 |
committer | Philipp Hagemeister <phihag@phihag.de> | Fri Sep 09 19:02:10 2016 +0200 |
tree | 7f6aa1df377467e4c592e441c2857917910ff1ca | |
parent | df3f95788c9db29a2abe8d531c2076351c0ab4a5 [diff] |
separate test and source code quality checks, and only run flake8 on newer versions
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?