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/* Copyright (c) 2002 Michael Stumpf <mistumpf@de.pepperl-fuchs.com>
Copyright (c) 2006,2009 Dmitry Xmelkov
All rights reserved.
Redistribution and use in source and binary forms, with or without
modification, are permitted provided that the following conditions are met:
* Redistributions of source code must retain the above copyright
notice, this list of conditions and the following disclaimer.
* Redistributions in binary form must reproduce the above copyright
notice, this list of conditions and the following disclaimer in
the documentation and/or other materials provided with the
distribution.
* Neither the name of the copyright holders nor the names of
contributors may be used to endorse or promote products derived
from this software without specific prior written permission.
THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"
AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR CONTRIBUTORS BE
LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR
CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF
SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS
INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN
CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE)
ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE
POSSIBILITY OF SUCH DAMAGE. */
/* $Id: modf.S 2191 2010-11-05 13:45:57Z arcanum $ */
#if !defined(__AVR_TINY__)
#include "fp32def.h"
#include "asmdef.h"
/* double modf (double x, double *iptr);
The modf() function breaks the argument x into an integral part and a
fractional part, each of which has the same sign as x. The integral part
is stored in iptr.
This implementation skips writing by zero pointer.
*/
#define iptr_lo r20
ENTRY modf
ENTRY modff
; save iptr
X_movw ZL, iptr_lo
; XH = exponent field
X_movw XL, rA2
lsl XL
rol XH
; B = A
X_movw rB0, rA0
X_movw rB2, rA2
; Is there an integral part?
subi XH, 127 ; exp of 1.0
brsh 1f
; fabs(x) < 1.0: *iptr = copysign(0, x), return x
clr rB0
clr rB1
clr rB2
andi rB3, 0x80
rjmp .L_write
; Is there a fraction part?
1: subi XH, 23
brsh 4f ; no fraction part
; check fraction: B >>= 23 - (exp-127)
mov XL, XH ; Now XH is -23..-1
clr r0 ; to control, is the fraction zero?
2: lsr rB2
ror rB1
ror rB0
adc r0, r1
inc XL
brmi 2b
tst r0
breq .L_nfrc ; fraction == 0
; restore and clear fraction: B <<= 23 - (exp-127)
3: lsl rB0
rol rB1
rol rB2
inc XH
brmi 3b
; write B
rcall .L_write
; return nonzero fraction: A - B
rjmp _U(__subsf3)
; exponent too big: compare with smallest NaN (0x7f800001)
4: cpi rA0, 1
cpc rA1, r1
ldi XL, 0x80
cpc rA2, XL
sbci XH, 128 - 23
brsh .L_write ; NaN: write and return as is
; fraction == 0
.L_nfrc:
X_movw rB0, rA0
X_movw rB2, rA2
; A = 0.0 with sign
clr rA0
clr rA1
clr rA2
andi rA3, 0x80
.L_write:
adiw ZL, 0 ; skip writing with NULL pointer
breq 1f
st Z, rB0
std Z+1, rB1
std Z+2, rB2
std Z+3, rB3
1: ret
ENDFUNC
#endif /* !defined(__AVR_TINY__) */