blob: 21fb7a6e8d32e7428679ce915cb1189ba9c2e683 [file] [log] [blame]
/*
* Copyright (c) 2014, 2018, Oracle and/or its affiliates. All rights reserved.
* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
*
* This code is free software; you can redistribute it and/or modify it
* under the terms of the GNU General Public License version 2 only, as
* published by the Free Software Foundation.
*
* This code is distributed in the hope that it will be useful, but WITHOUT
* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
* FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
* version 2 for more details (a copy is included in the LICENSE file that
* accompanied this code).
*
* You should have received a copy of the GNU General Public License version
* 2 along with this work; if not, write to the Free Software Foundation,
* Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
*
* Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
* or visit www.oracle.com if you need additional information or have any
* questions.
*
*/
#include "precompiled.hpp"
#include "utilities/debug.hpp"
#include "utilities/stringUtils.hpp"
int StringUtils::replace_no_expand(char* string, const char* from, const char* to) {
int replace_count = 0;
size_t from_len = strlen(from);
size_t to_len = strlen(to);
assert(from_len >= to_len, "must not expand input");
for (char* dst = string; *dst && (dst = strstr(dst, from)) != NULL;) {
char* left_over = dst + from_len;
memmove(dst, to, to_len); // does not copy trailing 0 of <to>
dst += to_len; // skip over the replacement.
memmove(dst, left_over, strlen(left_over) + 1); // copies the trailing 0 of <left_over>
++ replace_count;
}
return replace_count;
}
double StringUtils::similarity(const char* str1, size_t len1, const char* str2, size_t len2) {
assert(str1 != NULL && str2 != NULL, "sanity");
// filter out zero-length strings else we will underflow on len-1 below
if (len1 == 0 || len2 == 0) {
return 0.0;
}
size_t total = len1 + len2;
size_t hit = 0;
for (size_t i = 0; i < len1 - 1; i++) {
for (size_t j = 0; j < len2 - 1; j++) {
if ((str1[i] == str2[j]) && (str1[i+1] == str2[j+1])) {
++hit;
break;
}
}
}
return 2.0 * (double) hit / (double) total;
}